(2t^2+4t-16)=0

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Solution for (2t^2+4t-16)=0 equation:


Simplifying
(2t2 + 4t + -16) = 0

Reorder the terms:
(-16 + 4t + 2t2) = 0

Remove parenthesis around (-16 + 4t + 2t2)
-16 + 4t + 2t2 = 0

Solving
-16 + 4t + 2t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-8 + 2t + t2) = 0

Factor a trinomial.
2((-4 + -1t)(2 + -1t)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-4 + -1t)' equal to zero and attempt to solve: Simplifying -4 + -1t = 0 Solving -4 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1t = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1t = 0 + 4 -1t = 0 + 4 Combine like terms: 0 + 4 = 4 -1t = 4 Divide each side by '-1'. t = -4 Simplifying t = -4

Subproblem 2

Set the factor '(2 + -1t)' equal to zero and attempt to solve: Simplifying 2 + -1t = 0 Solving 2 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1t = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1t = 0 + -2 -1t = 0 + -2 Combine like terms: 0 + -2 = -2 -1t = -2 Divide each side by '-1'. t = 2 Simplifying t = 2

Solution

t = {-4, 2}

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